行内公式
{x∣Ax=b}
Xc∗<1,Xq∗<1
E=mc2
∂t∂
latex$E = mc^2$
$\frac{\partial}{\partial t}$
行间公式
E=mc2
a=dtdv=dtd(dtdre∗i+rdtdθe∗j)=dt2d2re∗i+dtdrdtde∗i+dtdrdtdθe∗j+rdt2d2θe∗j+rdtdθdtde_j
latex$ \vec a=\frac{d\vec v}{dt}=\frac{d(\frac{dr}{dt}\vec e_{i}+r\frac{d\theta}{dt}\vec e_{j})}{dt}=\frac{d^2r}{dt^2}\vec e_{i}+\frac{dr}{dt}\frac{d\vec e_{i}}{dt}+\frac{dr}{dt}\frac{d\theta}{dt}\vec e_{j}+r\frac{d^2\theta}{dt^2}\vec e_{j}+r\frac{d\theta}{dt}\frac{d\vec e_{j}}{dt} $
mt=gt
Vt=1
latex$ m_t=g_t $
$ V_t=1 $
ηt=lr∗Vtmt=lr∗gt
w_t+1=wt−ηt=wt−lr∗Vtmt=wt−lr∗gt
qs′′=−k∂x∂(T1+T2)x=0=qs′′−k∂x∂T1x=0−k∂x∂T2x=0→0=−k∂x∂T2x=0
latex$ \eta_t=lr*{\frac {m_t}{\sqrt V_t}}=lr*g_t $
$ w_{t+1}=w_t-\eta_t=w_t-lr*{\frac {m_t}{\sqrt V_t}}=w_t-lr*g_t $
<div text="red">
$
q''_s = -k \left.\frac{\partial }{\partial x} (T_1+T_2) \right|_{x=0} = \underbrace{-k \left.\frac{\partial T_1}{\partial x} \right|_{x=0}}_{q''_s} -k \left.\frac{\partial T_2}{\partial x} \right|_{x=0} \rightarrow \boxed{0 = -k \left.\frac{\partial T_2}{\partial x} \right|_{x=0}}
$
</div>
[acbd]
latex$
\begin{bmatrix}
a & b \\
c & d
\end{bmatrix}
$
{x=acosθy=bsinθ
latex$
\begin{equation}
\left\{
\begin{aligned}
x=a\cos\theta\\
y=b\sin\theta\\
end{aligned}
\right.
\end{equation}
$
